How can I write a progam that calculate age from current date to:year, month,day,hour?? (cosidering leap year?

I have to solve it with borland C++

How can I write a progam that calculate age from current date to:year, month,day,hour?? (cosidering leap year?
Something like this?





#include%26lt;stdio.h%26gt;


#include%26lt;conio.h%26gt;


#include%26lt;iostream.h%26gt;


#include%26lt;time.h%26gt;


#include%26lt;alloc.h%26gt;


#include%26lt;math.h%26gt;


char months[12][3]={"Jan","Feb","Mar","Apr","...


void main()


{


clrscr();


int j,d,m,y,day=0,month,year=0;


char ch;


char *p;


time_t tnow;


time(%26amp;tnow);


p=(char *)malloc(sizeof(tnow));


p=ctime(%26amp;tnow);


for(month=0;month%26lt;12;month++)


if(months[month][0]==p[4])


if(months[month][1]==p[5])


if(months[month][2]==p[6])


{


month++;


break;


}


for(j=0;j%26lt;4;j++)


year=(year*10)+abs(48-(int)p[j+20]);


day=abs(48-(int)p[8])*10+abs(48-(int)p...


wrong:


cout%26lt;%26lt;"enter the date of birth::";


cin%26gt;%26gt;d%26gt;%26gt;ch%26gt;%26gt;m%26gt;%26gt;ch%26gt;%26gt;y;


if(!(d%26gt;=1 %26amp;%26amp; d%26lt;=31 %26amp;%26amp; m%26gt;=1 %26amp;%26amp; m%26lt;=12)||(y%4==0 %26amp;%26amp; m==2 %26amp;%26amp; d%26gt;29) || (y%4!=0 %26amp;%26amp; m==2 %26amp;%26amp; d%26gt;28))


{


printf("You have entered wrong data\n");


goto wrong;


}


cout%26lt;%26lt;"Your current age is"


if(m%26lt;=month %26amp;%26amp; d%26lt;=day)


cout%26lt;%26lt;year-y;


else


cout%26lt;%26lt;(year-y-1);


getch();


}
Reply:Use excel sheet


put current date in date formatted cell


put your date of birth in another cell


get the dufference between above cells in formula assigned cell. You gaet exact no.of days.